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Editing v0.31 Talk:Temperature
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==Conversion corrections== | ==Conversion corrections== | ||
The conversions are faulty, if you should give many temperatures to konvert to, you should see to that the conversions are the same at more than one point...<br /> | The conversions are faulty, if you should give many temperatures to konvert to, you should see to that the conversions are the same at more than one point...<br /> | ||
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::::The conversions are still faulty, the conversion between Celsius and Kelvin is (C + 273 = K), so if the Celsius temperature is [DF scale] = [CELSIUS] * 9/5 + 10000 than Kelvin can't be [DF scale] = [KELVIN] * 9/5 + 9508.33. It should be [DF scale] = [KELVIN] * 9/5 + 9727 --[[User:Hypoaktivna ovca|Hypoaktivna ovca]] 15:45, 27 October 2010 (UTC) | ::::The conversions are still faulty, the conversion between Celsius and Kelvin is (C + 273 = K), so if the Celsius temperature is [DF scale] = [CELSIUS] * 9/5 + 10000 than Kelvin can't be [DF scale] = [KELVIN] * 9/5 + 9508.33. It should be [DF scale] = [KELVIN] * 9/5 + 9727 --[[User:Hypoaktivna ovca|Hypoaktivna ovca]] 15:45, 27 October 2010 (UTC) | ||
:::::The original was correct: C * 9/5 + 10000 = (K - 273.15) * 9/5 + 10000 = K * 9/5 - (273.15 * 9/5) + 10000 = K*9/5 - 491.67 + 10000 = K * 9/5 + 9508.33. One way to verify this is that zero Kelvin should give the same result as zero Rankine, since they are the same temperature; likewise 273.15 Kelvin and zero Celsius. --[[User:Neil|Neil]] 13:39, 29 October 2010 (UTC) | :::::The original was correct: C * 9/5 + 10000 = (K - 273.15) * 9/5 + 10000 = K * 9/5 - (273.15 * 9/5) + 10000 = K*9/5 - 491.67 + 10000 = K * 9/5 + 9508.33. One way to verify this is that zero Kelvin should give the same result as zero Rankine, since they are the same temperature; likewise 273.15 Kelvin and zero Celsius. --[[User:Neil|Neil]] 13:39, 29 October 2010 (UTC) | ||
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