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Editing Steel
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Latest revision | Your text | ||
Line 189: | Line 189: | ||
''s'' = 2 * (round_down(''j'') + p) | ''s'' = 2 * (round_down(''j'') + p) | ||
''s'' = 2 * (12 + 8) | ''s'' = 2 * (12 + 8) | ||
− | ''s'' = 2 * | + | ''s'' = 2 * 24 |
− | ''s'' = | + | ''s'' = 48 |
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'''Answer:''' | '''Answer:''' | ||
− | From 32 iron bars and 8 pig iron bars, | + | From 32 iron bars and 8 pig iron bars, 48 steel bars can be produced. Here is how: |
'''Plan:''' | '''Plan:''' | ||
− | * Stage 1: Issue 12 job orders to make pig iron bars. This will turn 12 iron bars into 12 pig iron bars. | + | * Stage 1: Issue 12 job orders to make pig iron bars. This will turn 12 iron bars into 12 pig iron bars. 24 of our original 32 iron bars will remain. 12 new pig iron bars are produced, increasing pig iron bar stocks from 8 to 24. |
− | * Stage 2: After stage 1 is completed, we will have | + | * Stage 2: After stage 1 is completed, we will have 24 iron bars and 24 pig iron bars. We issue 24 job orders to make steel bars (each job order will produce two steel bars). |
− | * Result: | + | * Result: 48 new steel bars, 0 iron bars, 0 pig iron bars left unused. |
Note: 10 metal bars can produce a full set of [[armor]] and a [[weapon]] for one [[soldier]]. | Note: 10 metal bars can produce a full set of [[armor]] and a [[weapon]] for one [[soldier]]. | ||